Apply a function iff some condition is met.

Apply a function n times to a given value.

stretchZipWith p z f xs ys stretches ys by inserting z in the places where p returns True

This has the effect of making the two lists have equal length by dropping the tail of the longer one.

filterByList takes a list of Bools and a list of some elements and filters out these elements for which the corresponding value in the list of Bools is False. This function does not check whether the lists have equal length.

filterByLists takes a list of Bools and two lists as input, and outputs a new list consisting of elements from the last two input lists. For each Bool in the list, if it is True, then it takes an element from the former list. If it is False, it takes an element from the latter list. The elements taken correspond to the index of the Bool in its list. For example:

filterByLists [True, False, True, False] "abcd" "wxyz" = "axcz"

This function does not check whether the lists have equal length.

partitionByList takes a list of Bools and a list of some elements and partitions the list according to the list of Bools. Elements corresponding to True go to the left; elements corresponding to False go to the right. For example, partitionByList [True, False, True] [1,2,3] == ([1,3], [2]) This function does not check whether the lists have equal length; when one list runs out, the function stops.

Like filter, only it reverses the sense of the test

Uses a function to determine which of two output lists an input element should join

Monadic version of partitionWith

spanEnd p l == reverse (span p (reverse l)). The first list returns actually comes after the second list (when you look at the input list).

Get the last two elements in a list.

onJust x m f applies f to the value inside the Just or returns the default.

`all2Prefix p xs ys` is a fused version of `and $ zipWith2 p xs ys`. (It generates good code nonetheless.) So if one list is shorter than the other, p is assumed to be True for the suffix.

`all3Prefix p xs ys zs` is a fused version of `and $ zipWith3 p xs ys zs`. (It generates good code nonetheless.) So if one list is shorter than the others, p is assumed to be True for the suffix.

(lengthExceeds xs n) = (length xs > n)

(lengthIs xs n) = (length xs == n)

(lengthIsNot xs n) = (length xs /= n)

(lengthAtLeast xs n) = (length xs >= n)

(lengthAtMost xs n) = (length xs <= n)

(lengthLessThan xs n) == (length xs < n)

atLength atLen atEnd ls n unravels list ls to position n. Precisely:

 atLength atLenPred atEndPred ls n
  | n < 0         = atLenPred ls
  | length ls < n = atEndPred (n - length ls)
  | otherwise     = atLenPred (drop n ls)

True if length xs == length ys

True if length xs <= length ys

True if length xs < length ys

Utility function to go from a singleton list to it's element.

Wether or not the argument is a singleton list is only checked in debug builds.

Extract the single element of a list and panic with the given message if there are more elements or the list was empty. Like expectJust, but for lists.

Like expectJust msg . nonEmpty; a better alternative to fromList.

Split a list into its last element and the initial part of the list. snocView xs = Just (init xs, last xs) for non-empty lists. snocView xs = Nothing otherwise. Unless both parts of the result are guaranteed to be used prefer separate calls to last + init. If you are guaranteed to use both, this will be more efficient.

Compute all the ways of removing a single element from a list.

holes [1,2,3] = [(1, [2,3]), (2, [1,3]), (3, [1,2])]

Replace the last element of a list with another element.

Merge an unsorted list of sorted lists, for example:

mergeListsBy compare [ [2,5,15], [1,10,100] ] = [1,2,5,10,15,100]

\( O(n \log{} k) \)

Given two lists xs and ys, return `splitAt (length xs) ys`.

drop from the end of a list

Convert a word to title case by capitalising the first letter

Remove duplicates but keep elements in order. O(n * log n)

Remove duplicates but keep elements in order. O(n * log n)

Search for possible matches to the users input in the given list, returning a small number of ranked results

Determine the $log_2$ of exact powers of 2

Parse a string into a significand and exponent. A trivial example might be: ghci> readSignificandExponentPair "1E2" (1,2) In a more complex case we might return a exponent different than that which the user wrote. This is needed in order to use a Integer significand. ghci> readSignificandExponentPair "-1.11E5" (-111,3)

Parse a string into a significand and exponent according to the "Hexadecimal Floats in Haskell" proposal. A trivial example might be: ghci> readHexSignificandExponentPair "0x1p+1" (1,1) Behaves similar to readSignificandExponentPair but the base is 16 and numbers are given in hexadecimal: ghci> readHexSignificandExponentPair "0xAp-4" (10,-4) ghci> readHexSignificandExponentPair "0x1.2p3" (18,-1)

A sample hash function for Strings. We keep multiplying by the golden ratio and adding. The implementation is:

hashString = foldl' f golden
  where f m c = fromIntegral (ord c) * magic + hashInt32 m
        magic = 0xdeadbeef

Where hashInt32 works just as hashInt shown above.

Knuth argues that repeated multiplication by the golden ratio will minimize gaps in the hash space, and thus it's a good choice for combining together multiple keys to form one.

Here we know that individual characters c are often small, and this produces frequent collisions if we use ord c alone. A particular problem are the shorter low ASCII and ISO-8859-1 character strings. We pre-multiply by a magic twiddle factor to obtain a good distribution. In fact, given the following test:

testp :: Int32 -> Int
testp k = (n - ) . length . group . sort . map hs . take n $ ls
  where ls = [] : [c : l | l <- ls, c <- ['\0'..'\xff']]
        hs = foldl' f golden
        f m c = fromIntegral (ord c) * k + hashInt32 m
        n = 100000

We discover that testp magic = 0.

A call stack constraint, but only when isDebugOn.